Optimal. Leaf size=200 \[ -\frac{3 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^7 (b d-a e)}{7 e^4 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^6 (b d-a e)^2}{2 e^4 (a+b x)}-\frac{\sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^5 (b d-a e)^3}{5 e^4 (a+b x)}+\frac{b^3 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^8}{8 e^4 (a+b x)} \]
[Out]
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Rubi [A] time = 0.415269, antiderivative size = 200, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071 \[ -\frac{3 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^7 (b d-a e)}{7 e^4 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^6 (b d-a e)^2}{2 e^4 (a+b x)}-\frac{\sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^5 (b d-a e)^3}{5 e^4 (a+b x)}+\frac{b^3 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^8}{8 e^4 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[(d + e*x)^4*(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 25.562, size = 163, normalized size = 0.82 \[ \frac{\left (d + e x\right )^{5} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{8 e} + \frac{\left (3 a + 3 b x\right ) \left (d + e x\right )^{5} \left (a e - b d\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{56 e^{2}} + \frac{\left (d + e x\right )^{5} \left (a e - b d\right )^{2} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{56 e^{3}} + \frac{\left (d + e x\right )^{5} \left (a e - b d\right )^{3} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{280 e^{4} \left (a + b x\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((e*x+d)**4*(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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Mathematica [A] time = 0.147611, size = 215, normalized size = 1.08 \[ \frac{x \sqrt{(a+b x)^2} \left (56 a^3 \left (5 d^4+10 d^3 e x+10 d^2 e^2 x^2+5 d e^3 x^3+e^4 x^4\right )+28 a^2 b x \left (15 d^4+40 d^3 e x+45 d^2 e^2 x^2+24 d e^3 x^3+5 e^4 x^4\right )+8 a b^2 x^2 \left (35 d^4+105 d^3 e x+126 d^2 e^2 x^2+70 d e^3 x^3+15 e^4 x^4\right )+b^3 x^3 \left (70 d^4+224 d^3 e x+280 d^2 e^2 x^2+160 d e^3 x^3+35 e^4 x^4\right )\right )}{280 (a+b x)} \]
Antiderivative was successfully verified.
[In] Integrate[(d + e*x)^4*(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Maple [A] time = 0.011, size = 264, normalized size = 1.3 \[{\frac{x \left ( 35\,{b}^{3}{e}^{4}{x}^{7}+120\,{x}^{6}a{b}^{2}{e}^{4}+160\,{x}^{6}{b}^{3}d{e}^{3}+140\,{x}^{5}{a}^{2}b{e}^{4}+560\,{x}^{5}a{b}^{2}d{e}^{3}+280\,{x}^{5}{b}^{3}{d}^{2}{e}^{2}+56\,{x}^{4}{a}^{3}{e}^{4}+672\,{x}^{4}{a}^{2}bd{e}^{3}+1008\,{x}^{4}a{b}^{2}{d}^{2}{e}^{2}+224\,{x}^{4}{b}^{3}{d}^{3}e+280\,{x}^{3}{a}^{3}d{e}^{3}+1260\,{x}^{3}{a}^{2}b{d}^{2}{e}^{2}+840\,{x}^{3}a{b}^{2}{d}^{3}e+70\,{x}^{3}{b}^{3}{d}^{4}+560\,{a}^{3}{d}^{2}{e}^{2}{x}^{2}+1120\,{a}^{2}b{d}^{3}e{x}^{2}+280\,a{b}^{2}{d}^{4}{x}^{2}+560\,x{a}^{3}{d}^{3}e+420\,x{a}^{2}b{d}^{4}+280\,{a}^{3}{d}^{4} \right ) }{280\, \left ( bx+a \right ) ^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((e*x+d)^4*(b^2*x^2+2*a*b*x+a^2)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(e*x + d)^4,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.206402, size = 304, normalized size = 1.52 \[ \frac{1}{8} \, b^{3} e^{4} x^{8} + a^{3} d^{4} x + \frac{1}{7} \,{\left (4 \, b^{3} d e^{3} + 3 \, a b^{2} e^{4}\right )} x^{7} + \frac{1}{2} \,{\left (2 \, b^{3} d^{2} e^{2} + 4 \, a b^{2} d e^{3} + a^{2} b e^{4}\right )} x^{6} + \frac{1}{5} \,{\left (4 \, b^{3} d^{3} e + 18 \, a b^{2} d^{2} e^{2} + 12 \, a^{2} b d e^{3} + a^{3} e^{4}\right )} x^{5} + \frac{1}{4} \,{\left (b^{3} d^{4} + 12 \, a b^{2} d^{3} e + 18 \, a^{2} b d^{2} e^{2} + 4 \, a^{3} d e^{3}\right )} x^{4} +{\left (a b^{2} d^{4} + 4 \, a^{2} b d^{3} e + 2 \, a^{3} d^{2} e^{2}\right )} x^{3} + \frac{1}{2} \,{\left (3 \, a^{2} b d^{4} + 4 \, a^{3} d^{3} e\right )} x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(e*x + d)^4,x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \left (d + e x\right )^{4} \left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x+d)**4*(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.21543, size = 482, normalized size = 2.41 \[ \frac{1}{8} \, b^{3} x^{8} e^{4}{\rm sign}\left (b x + a\right ) + \frac{4}{7} \, b^{3} d x^{7} e^{3}{\rm sign}\left (b x + a\right ) + b^{3} d^{2} x^{6} e^{2}{\rm sign}\left (b x + a\right ) + \frac{4}{5} \, b^{3} d^{3} x^{5} e{\rm sign}\left (b x + a\right ) + \frac{1}{4} \, b^{3} d^{4} x^{4}{\rm sign}\left (b x + a\right ) + \frac{3}{7} \, a b^{2} x^{7} e^{4}{\rm sign}\left (b x + a\right ) + 2 \, a b^{2} d x^{6} e^{3}{\rm sign}\left (b x + a\right ) + \frac{18}{5} \, a b^{2} d^{2} x^{5} e^{2}{\rm sign}\left (b x + a\right ) + 3 \, a b^{2} d^{3} x^{4} e{\rm sign}\left (b x + a\right ) + a b^{2} d^{4} x^{3}{\rm sign}\left (b x + a\right ) + \frac{1}{2} \, a^{2} b x^{6} e^{4}{\rm sign}\left (b x + a\right ) + \frac{12}{5} \, a^{2} b d x^{5} e^{3}{\rm sign}\left (b x + a\right ) + \frac{9}{2} \, a^{2} b d^{2} x^{4} e^{2}{\rm sign}\left (b x + a\right ) + 4 \, a^{2} b d^{3} x^{3} e{\rm sign}\left (b x + a\right ) + \frac{3}{2} \, a^{2} b d^{4} x^{2}{\rm sign}\left (b x + a\right ) + \frac{1}{5} \, a^{3} x^{5} e^{4}{\rm sign}\left (b x + a\right ) + a^{3} d x^{4} e^{3}{\rm sign}\left (b x + a\right ) + 2 \, a^{3} d^{2} x^{3} e^{2}{\rm sign}\left (b x + a\right ) + 2 \, a^{3} d^{3} x^{2} e{\rm sign}\left (b x + a\right ) + a^{3} d^{4} x{\rm sign}\left (b x + a\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(e*x + d)^4,x, algorithm="giac")
[Out]